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To find value of k Let a=b=c , Now ,lets take a=b=c=1 so, 1+1/1 =k therefore, k=2 Now, a=b=c= 2 so, 2+2/2 =k therefore , k=2 now let's take a=b=c=7 So, 7+7/7 = k therefore, k=2 So you can see to find the value we have to assume that a=b=c as there. C t H V E A N Z X. Z N g V b v ̘V ܁ASHIPS( V b v X) ̌ T C g E c I C V b v BSC:.

A) If 2A(g) + B(g) → C(g) Kc = 9,541 What is Kc for C(g) → 2A(g) + B(g)?. L b g ł ҂ ł T C g A ҂ ɉ ă L O ` ŏЉ Ă ܂ B 50 ~ ҂ ݑ N T C g ƁA ^ b v ŊȒP ɉ҂ X } z T C g y ł ߂ł B S āAPC ƃX } z ̗ ɑΉ Ă 邨 T C g ł B. ¸ Ò'ö#.* _ > e 8 O C T I 8 2 "K^ Ô ç ¤ ´ Õ ç ® ¢ ñ » Ó Æ.

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The goal is to get K all by itself on one side of the equation. 62 = H > B R G B D g Z F b g g h _ h e h ` d b y m g b \ _ j k b l _ l “ K \. Z N g V b v ̘V ܁ASHIPS( V b v X) ̌ T C g E c I C V b v BSHIPS any:.

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If a^x=b b^y=c c^z=a Prove xyz=1 Please give the solution a x =b => x=log a b b y =c=> y=log b c c z =a=> z=log c a xyz=(log a b.log b c).log c a =log. _ ^ W S G } ' c !. T @ h g ĊȒP Ƀt @ h ̍i 荞 ݂ ł ܂ B L h Ⓤ A t @ h ^ C v ȂǁA L x B Ȃ D ݂̃t @ h Ă I.

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=¶e fg8h ^g b y@ ' ìí '± ' 9 9 @ k-" ' =:c =h i8~<b i8:. Instructions on balancing chemical equations:. A Formula for C(n,k) We would like to obtain a formula to calculate C(n,k) without writing down Pascal's triangle (although, to be honest, it is generally faster to write down Pascal's triangle than it is to use this formula, especially if you need a number of these binomial coefficients).

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03/13/09 at 14:26:59 From:. “Helping you to get your children through the 11 Plus and into a school of your choice.” Verbal Reasoning Type U - Letter Relationships A B C D E F G H I J K L M. Molar mass - g/mol, weight - g.

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Please tell about this free chemistry software to your friends!. K N k k k N N N k N k k k N N N N k N k k k x x x x a a a a a a x x x x a a a a from MATH 225 at Bilkent University. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.

He provides courses for Maths and Science at Teachoo. When n is negative, say n = -m, then c^(-m) = a^(-m) + b^(-m) is equivalent (when abc is nonzero) to c^(-m) = (a^m + b^m)/(ab)^m c^m = (ab)^m/(a^m + b^m) c^m(a^m + b^m) = (ab)^m (ac)^m + (bc)^m = (ab)^m and so by Fermat's Last Theorem, there are no integer solutions when. S Salmo-Fario blog m Profile :.

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Fermat's last theorem Hi Tim, Thanks for writing to Dr.